J.R. S. answered 11/15/20
Ph.D. University Professor with 10+ years Tutoring Experience
2LiOH(s) + CO2(g) ==> Li2CO3(s) + H2O(l) ... balanced equation
Using the stoichiometry of the balanced equation along with the molar masses of LiOH and CO2, we can answer the question as follows:
23.7 g LiOH x 1 mol LiOH / 23.9 g x 1 mol CO2 / 2 mol LiOH x 44 g CO2/mol CO2 = 21.8 g CO2