Methanol can be formed by the following UNBALANCED equation below. What is the mass in grams of methanol that can be formed from 167 molecules of CO? H₂(g) + CO(g) → CH₃OH(l).

Answer 1

2H₂(g) + CO(g) ==> CH₃OH(l) ... balanced equation

Using the stoichiometry of the balanced equation along with Avogadro's number and the molar mass of methanol, we can answer this question as follows:

167 molecules CO x 1 molecule CH₃OH/molecule CO x 1 mol CH₃OH/6.02x10²³ molecules = 2.77x10^-22mol CH₃OH

2.77x10^-22 mol CH₃OH x 32.0 g CH₃OH/mol = 8.88x10^-21 g CH₃OH