How many moles of lithium hydroxide would be required to produce 48.5 g of Li₂CO₃ in the following chemical reaction? 2 LiOH(s) + CO₂(g) → Li₂CO₃(s) + H₂O(l)

Answer 1

2LiOH(s) + CO₂(g) ==> Li₂CO₃(s) + H₂O(l) ... balanced equation

Using the stoichiometry of the balanced equation, along with the molar mass of Li₂CO₃ and dimensional analysis, we can answer this question as follows:

48.5 g Li₂CO₃ x 1 mol Li₂CO₃ / 73.9 g x 2 mol LiOH / 1 mol Li₂CO₃ = 1.31 moles LiOH needed