How many moles of HNO₃ will be produced from the reaction of 34.5 g of NO₂ with excess water in the following chemical reaction? 3 NO₂(g) + H₂O (l) → 2 HNO₃(g) + NO(g)

Answer 1

3NO₂(g) + H₂O(l) ==> 2HNO₃(g) + NO(g) ... balanced equation

Using the stoichiometry of the balanced equation along with the molar mass of NO2 and dimensional analysis, we can answer the question as follows:

34.5 g NO₂ x 1 mol NO₂ / 46 g x 2 mol HNO₃ / 3 mol NO₂ = 0.500 moles HNO₃