How many moles of NaOH are present in 30.0 mL of 0.110 M NaOH?

Question

How many moles of NaOH are present in 30.0 mL of 0.110 M NaOH?

Answer 1

30.0 ml = 0.0300 L

0.110 M NaOH = 0.110 mole NaOH/L

moles present = 0.0300 L x 0.110 mol/L = 0.00330 moles NaOH present