If the initial temperature of an ideal gas at 2.250 atm is 62.00 ∘C, what final temperature would cause the pressure to be reduced to 1.700 at

Answer 1

Given:

T1 = initial temperature = 62.00ºC + 273.15 = 335.15K

P1 = initial pressure = 2.250 atm

P2 = final pressure = 1.700 atm

Asked for:

T2 = ? K

Assuming constant volume:

P1/T1 = P2/T2

T2 = P2T1 / P1 = (1.700 atm)(335.15K) / 2.250 atm

T2 = 253.2K