A sample of an ideal gas has a volume of 3.60 L at 12.60 ∘C and 1.50 atm. What is the volume of the gas at 22.80 ∘C and 0.986 atm?

Answer 1

Convert temperatures to Kelvin (add 273.15)

Use combined gas law P1V1/T1 = P2V2/T2

(1.50 atm)(3.60 L) / 285.75K = (0.986 atm)(V2) / 295.95

Solve for V2 in liters