Adrian M. answered 11/11/20
Experienced Math Tutor for all Backgrounds
Since the reduction formulas only talk about powers of 2, we're going to have to rewrite the equation:
sin4(8x) = [sin2(8x)]2
Now using the reduction formula sin2x = .5[1- cos(2x)], we have:
[sin2(8x)]2 = [.5(1 - cos(2(8x)]2 = [.5(1 - cos(16x)]2
Expanding this out using (a + b)2 = a2 + 2ab + b2:
[.5(1 - cos(16x)]2 = .25(1 - 2cos(16x) + cos2(16x))
Here we have to use the reduction formula cos2x = .5[1 + cos(2x)]:
.25[1 - 2cos(16x) + cos2(16x)] = .25[1 - 2cos(16x) + .5[1 + cos(2(16x))]
Simplify:
.25[1 - 2cos(16x) + .5[1 + cos(2(16x))]
.25[1 - 2cos(16x) + .5 + .5cos(32x)]
.25[1.5 - 2cos(16x) + .5cos(32x)]
Adrian M.
Thank you for letting me know! I just fixed it11/11/20