What volume in mL of 1.62 M NaOH is required to react with 26.9 of 1.25 M citric acid according to the following reaction? H3 C6H5O7 (aq)+3NaOH(aq) 3H 2 O(l)+Na 3 C 6 H 5 O 7 (aq)

Answer 1

moles Citric acid = 26.9 ml x 1 L/1000 ml x 1.25 mol/L = 0.0336 moles

moles NaOH needed = 3 x 0.0336 = 0.100 moles

mls NaOH needed = 0.100 moles x 1000 mls/1.62 moles = 62.3 mls