How many moles of H₂ are required to produce -2501 kJ of heat in the following reaction? N₂ (g) + 3 H₂ (g) → 2 NH₃ (g) ∆H° = -91.8 kJ/mol

Question

How many moles of H₂ are required to produce -2501 kJ of heat in the following reaction? N₂ (g) + 3 H₂ (g) → 2 NH₃ (g) ∆H° = -91.8 kJ/mol

Answer 1

N₂(g) + 3H₂(g) ==> 2NH₃(g) ∆Hº = -91.8 kJ/mol

3 moles H₂ in the reaction generates 91.8 kJ, so how many moles of H₂ will generate 2501 kJ?

2501 kJ x 3 moles H₂ / 91.8 kJ = 81.7 moles H₂