Consider the reaction: N2 (g) + 3 H2 (g) 2 NH3 (g) Kc = 152 at 225°C

Question

Calculate the concentration of H2 at equilibrium, if [NH3] = 0.117 M and [N2] = 0.0935 M.

Answer 1

N₂(g) + 3H₂(g) ===> 2NH₃(g)

Kc = [NH₃]² / [N₂][H₂]³

152 = (0.117)² / (0.0935)(x)³

x3 = 9x10-5

x = 4.48x10^-2 M = 0.0448 M = [H₂]