If the point P(−4/5,y) is on the unit circle in quadrant II, then y=

Answer 1

y=3/5

(-4/5)^2 + y^2 = 1

y^2 = 1 - 16/25 = 9/25

y = sqr(9/25) = 3/5. only the positive square root is in 2nd quadrant.