Calorimetry and Heat Capacity

Question

At constant volume, the heat of combustion of a particular compound is -3360.3 kJ/mol. When 1.541 g of this compound (molar mass is 128.08 g/mol) was burned in a bomb calorimeter, the temperature of the calorimeter (including its contents) rose by 3.069 °C. What is the heat capacity of the calorimeter in J/°C? 

Answer 1

q = C_cal∆T

moles 1.541 g x 1 mol/128.08 g = 0.01203 moles

q = -3360.3 kJ/mol x 0.01203 moles = 40.43 kJ = 40430 J

C_cal = ?

∆T = 3.069º

40430 J = (C)(3.069º)

C_cal = 13,174 J/º