Any help would be appreciated.

Question

Write a equivalent expression to √24x²y⁷z⁸ / y^^-4z²

Answer 1

√[(24x²y⁷z⁸) / (y^-4z²)] = 2√6√x²√y¹¹√z⁶ = 2√6 x √y¹⁰√y z³ = 2xy⁵z³ √(6y)

Answer 2

subtract the powers in the numerator from powers in the denominator for y and z

to get 2sqr6(x)^2(y)^11(z)^6

7- (-4) = 7+4= 11 for the power of y

8-2 = 6 for the power of z

sqr24 = sqr(4)sqr6= 2sqr6

that's assuming the square root sign only referred to the constant 24 and not to x, y and z terms