J.R. S. answered 11/09/20
Ph.D. University Professor with 10+ years Tutoring Experience
2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(g)
227..............0.................-393.5........-241.8..........∆H values
∆Hrxn = ∑products - ∑reactants
∆Hrxn = (4x-393.5) + (2x-241.8) - (2x227) = -1574 + (-483.6) - 454
∆Hrxn = -2512 kJ/mol-K
2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(g)
200.9........205............213.7........188.7..........S values
∆S = ∑products - ∑reactants
∆S = 4x213.7 + 2x188.7 - 2x200.9 + 5x205
∆S = 855 + 377 - 402 + 1025
∆S = 1232 - 1427
∆S = -195 J/mol-K