Tom K. answered 11/08/20
Knowledgeable and Friendly Math and Statistics Tutor
sin4(x)cos2(x) = 1/4(4sin2(x)cos2(x))sin2(x)) = 1/4sin2(2x)sin2(x) = 1/16(cos(x) - cos(3x))2 =
1/16cos2(x) - 1/8cos(x)cos(3x) + 1/16cos2(3x) =
1/32 + 1/32cos(2x) - 1/16 cos(4x) - 1/16 cos(2x) + 1/32 + 1/32cos(6x) =
1/16 - 1/32cos(2x) - 1/16 cos(4x) + 1/32 cos(6x)
Answer was verified by comparing the final function with the initial function on [0, 2π)