The coordinates of the vertices of a triangle are D(5, 6), E(7, 5), and F(4, 3). Find the perimeter of the triangle.

Answer 1

sqr10 + sqr13 + sqr5

take the square root of the sum of the changes in y plus change in x for each side of the triangle

add them up

(6-3)^2 + (5-4)^2 = 9+1 = 10. Take the sqr10

((6-5)^2 + (5-7)^2 = 1 + 4 = 5 sqr5

(5-3)^2 + (7-4)^2 = 4 + 9 = 13 sqr13

add the 3 square roots to get the perimeter.