J.R. S. answered 11/07/20
Ph.D. University Professor with 10+ years Tutoring Experience
1). Since we have the mass (11.003 g), and are asked for the molar mass, that means we MUST find the number of moles because molar mass = g / moles. So, let's find the number of moles of gas:
PV = nRT (change 760 torr to 1 atm)
n = PV/RT = ( 1 atm)(6.63 L) / (0.0821 Latm/Kmol)(310K) = 0.2605 moles
molar mass = 11.003 g / 0.2605 moles = 42.24 g/mol
2). Unfair question. There could be many, many gases that have this molar mass. One possible guess would be PROPENE (C3H6)