Show your work for determining the amount of grams of CuSO4x5H2O solid needed to prepare the 20.0mL, 0.200 M CuSO4 solution.

Answer 1

Molar mass CuSO₄x5H₂O = 249.69 g/mol

20.0 ml = 0.0200 L

0.200 M = 0.200 moles/L

Moles CuSO₄ needed = 0.0200 L x 0.200 mol/L = 0.004 moles CuSO₄ needed

Since 1 mole CuSO₄x5H₂O contains 1 mole CuSO₄, we need 0.004 moles CuSO₄x5H₂O

grams CuSO₄x5H₂O needed = 0.004 moles CuSO₄x5H₂O x 249.,69 g/mol = 0.999 g (3 sig. figs.)