Find a possible formula for the trigonometric function whose values are in the following table

Question

x= 0,3,6,9,12,15,18

y= -3,-6,-3,0,-3,-6,-3

y=

Answer 1

First thing you should do is to plot the points and you will see this is a negative sine graph. It starts at the midline of -3, goes down to its minimum, returns to the midline ,goes up to its max and then returns to midline

Vertical shift is -3(d)

amplitude is 3 (a)

no phase shift (c=0)

period is 12 so b = 2pi/12 = pi/6(b)

Equation is y= -3sin[(pi/6) x] -3