How do I find a 90% confidence interval for this population proportion?

Question

looking at a poll, 73% of California adults (367 out of 506 surveyed) believe that education is one of the main issues facing California. We wish to construct a 90% confidence interval for the true proportion of California adults who believe that education is one of the main issues facing California.

I need help finding a 90% confidence interval for the population proportion. I keep getting it wrong so if someone could explain the steps that would be nice

Answer 1

phat = sample proportion = 0.73

n = sample size = 506

critical z value for 90% confidence = 1.645

confidence interval = phat +/- z-critical*sqrt(phat*(1-phat)/n)

0.73 +/- 1/645 * sqrt(0.73*0.27/506)

you can complete the rest.