Find the equation of the line that is parallel to the given line and passes through the given point.

Question

y = -2x+6;(3,1)

The equation is y=

Answer 1

for equation of form y=mx + b, slope = m and y-intercept is b

for equation y=-2x + 6, m = slope = -2

a line parallel to that line has the same slope,

so the equation of that line so far is

y = -2x + b

since the line passes through (3,1), we can replace x with 3 and y with 1 and solve for b:

1 = -2(3) + b

7 = b

so equation of line is:

y = -2x + 7