write the equation of a line that is parallel to y=0.6x+3 and that passes through the point (-3 -5)

Question

i need the equation for the answer

Answer 1

In order for a line to be parallel they must have the same slope.

Therefore, m = 0.6

Now, apply the points to the equation of the line and solve for b

Y = mx+b

-5 = 0.6 * -3 + b

b = -3.2

Y = 0.6x - 3.2