What is the perimeter of the triangle with vertices at (0,2), (-1,3), and (-3,-6)?

Answer 1

Perimeter P of a triangle with 3 sides a, b, c is P = a + b + c

here in the problem 3 vertices are given , you have to calculate the distace or length of the 3 lines a, b , c

so the formula of the distance d = √( x₂ - x₁ )²+ ( y₂- y₁)²

^{if we consider co-ordinates 2 vertices (0, 2) , ( -1, 3 ) and plugging the values the distance formula we get,}

^{d = √2 = say one side a}

^{similar way we can find for other 2 vertices ( -1,3 ) and ( -3, -6)}

^{d = √85 = say side b ....similarly you get side c}

^{after you get all 3 sides you will plug in values in P = a + b+ c ....................hope this helps you}

Answer 2

For this problem you will need to use the distance formula d= sqrt((x1-x2)²+(y1-y2)²). You will need to do this 3 times which each combination of coordinates to get the 3 sides of the triangle.