Standard enthalpy formation

Question

A scientist measures the standard enthalpy change for the following reaction to be 160.2 kJ:

CaCO₃(s)CaO(s) + CO₂(g)

Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of CO₂(g) is BLANK  kJ/mol

Please walk through the steps on how to get to the answer.

Answer 1

To find the standard enthalpy of reaction (∆Hºrxn), you subtract the standard enthalpy of formation (∆Hºf) of the reactants from that of the products, i.e. ∑∆H_fproducts - ∑∆H_freactants. To do this, you need a table of ∆Hf values for the different compound in the equation, which you do not supply. So, I can't answer the problem with actual values, but will tell you how to do it.

Look up ∆Hfº CaO(s)

Look up ∆Hfº CaCO3(s)

Then use this equation:

160.2 kJ = ∆Hfº CaO(s) + ∆Hf CO2 - ∆Hfº CaCO3(s)

and solve for ∆Hf CO2