Ok, so the middle 50% is the IQR. So we are essentially looking at the 25 percentile and the 75 percentile. So now we just have to look on the Z table to see which Z score is greater than or equal to the lowest 25 percent of Z scores. Same with the 75 percentile. So we know:
For the .25 area, Z=-0.674
For the .75 area, Z = 0.674.
So we just need to find y. So, now we have 0.674=x-100/15
15*.674=x-100
-10.11=x-100
100-10.11=x
89.89=x
We also need to plug in:
10.11=x-100
110.11
.674=x-100/15
So the middle 50% of scores fall in between 89.89 and 110.11