J.R. S. answered 11/04/20
Ph.D. University Professor with 10+ years Tutoring Experience
V1C1 = V2C2
V1 = initial concentration = x ml
C1 = initial concentration = 80.0 g/ml
V2 = final volume = 25.00 ml
C2 = final concentration = 5.0 g/ml
(x ml)(80.0 g/ml) = (25.00 ml)(5.0 g/ml)
x = 1.56 ml of stock solution
25.00 ml - 1.56 ml = 23.44 ml of water
With the correct use of significant figures, you would have only 2 sig. figs. in your answer to volume of stock, so it would be 1.6 ml (5.0 g/ml has only 2 sig. figs.). When subtracting this volume from 25.00 mls, we would limit our answer to one decimal place and arrive at 23.4 mls of water to be added.