What is K for a reaction if ∆G° =-221.1 kJ/mol at 25°C? (R = 8.314 J/mol ･ K)

Answer 1

ln K = -∆Gº/RT

∆Gº = 221.1 kJ/mol

R = 8.314 J/Kmol but since ∆Gº is in units of kJ, we'll change this to 0.008314 kJ/Kmol

T = 25ºC + 273 = 298K

ln K = - (-221.1 kJ/mol) / (0.008314 kJ/Kmol)(298)

ln K = 89.24

K = 5.71x10³⁸