most likely number of wins = 915 * 0.48 = 439.2
standard deviation = square root(915*0.48*0.52) = 15.11
[439.2-2*15.11,439.2+15.11*2] = [408.98,469.42]
Tiffany C.
asked 11/03/20You are playing a card came, and the probability that you will win a game is p=0.48.
If you play the game 915 times, what is the most likely number of wins?=
(Round answer to one decimal place.)
μ = Let X represent the number of games (out of 915) that you win. Find the standard deviation for the probability distribution of X.
(Round answer to two decimal places.)
σ =
The range rule of thumb specifies that the minimum usual value for a random variable is μ–2σ and the maximum usual value is μ+2σ. You already found μ and σ for the random variable X.
Use the range rule of thumb to find the usual range of X values. Enter answer as an interval using square-brackets and only whole numbers.usual values =
most likely number of wins = 915 * 0.48 = 439.2
standard deviation = square root(915*0.48*0.52) = 15.11
[439.2-2*15.11,439.2+15.11*2] = [408.98,469.42]
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