J.R. S. answered 11/03/20
Ph.D. University Professor with 10+ years Tutoring Experience
1). To convert ºC to K (Kelvin), we add 273.15, so 20ºC = 293.15K.
V1 = initial volume = 0.20 m3 = 200 L
T1 = initial temperature = 293K
V2 = final volume = 400 L
T2 = final temperature = ?
V1/T1 = V2/T2
T2 = V2T1/V1 = 586K - 273 = 313ºC
2). V1 = 30 L
T1 = 20C + 273 = 293K
V2 = ?
T2 = -146.5C + 273 = 126.5
V1/T1 = V2/T2
V2 = V1T2 / T1
V2 = 13 L
3). V1 = 125 L
T1 = ?
V2 = 75 L
T2 = 225C + 273 = 498K
V1/T1 = V2/T2
T1 = V1T2 / V2
T1 = 830K -273 = 557ºC