J.R. S. answered 11/02/20
Ph.D. University Professor with 10+ years Tutoring Experience
Looking at the periodic table we see that Se (selenium) is atomic number 34, and is in period 4 and group 16.
The valence electrons would therefore be in the 4p subshell and there would be 4 such valence electrons. So, the valence electrons would have the configuration of 4p. For this configuration, n = 4 and l = 1 so it would be choice (II).