Standard Heat of formation

Question

A. Write the balanced chemical equation that represents the standard heat of formation of KCl(s) at 298 K.

Use the pull-down boxes to specify states. Write fractions with a slash, such as 1/2 for one half. If a box is not needed leave it blank.

B. (b) The standard enthalpy change for the following reaction is -1.11×10³ kJ at 298 K.

1. 2 Cr(s) + 3 Cl₂(g)2 CrCl₃(s)

What is the standard heat of formation of CrCl₃(s)?  Kj/mol

Answer 1

A). K(s) + 1/2 Cl₂(g) ==> KCl(s)

B). It would be 1/2 of -1.11x10³ kJ since this is the value for the formation of TWO moles of CrCl₃(s). So the value for the formation of ONE mole of CrCl₃ is 5.55x10² kJ/mole