If 4.04 mol of C5H12 reacts with excess O2, how many moles of CO2 will be produced by the following combustion reaction?

Question

If  mol of  reacts with excess  how many moles of  will be produced by the following combustion reaction?

C5H12+8O2⟶6H2O+5CO2

Answer 1

C₅H₁₂ + 8O₂ ==> 5CO₂ + 6H₂O ... balanced equation for combustion of pentane

4.04 moles C₅H₁₂ x 5 mol CO₂ / 1 mol C₅H₁₂ = 20.2 moles CO₂