A chemist requires 0.787 mol Na2CO3 for a reaction. How many grams does this correspond to? mass: g Na2CO3

Answer 1

molar mass Na₂CO₃ = 106 g/mole

Using dimensional analysis:

0.787 moles Na₂CO₃ x 106 g/mole Na₂CO₃ = g Na₂CO3

Answer = 83.4 g Na₂CO₃