Sid E.
asked • 11/01/20Trigonometry Question
2. A hot air balloon is to be attached to the grond using two support ropes. One support is attached on one side of the balloon at an angle of elevation of 42 degrees. Another support is attached on the other side of the balloon at an angle of elevation of 50 degrees. The distance between the locations the supports are attached on the ground is 40m.
a) How long is the rope that is attached at the 42degrees ?
b) How high is the balloon.
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1 Expert Answer
X1 + x2 = 40 m
tan42 =y/l1
tan50 =y/l2
0.9 = y/x1
1.19= y/x2
0.9 l1 +1.19 l2 = 40
cos 42 = x1/l1
Cos 50 = x2/l2
0.74 = x1/l1
0.64 = x2/l2
x1 = 40 - x2
l1 =( 40-x2)/0.74
Calculate y = Height of Balloon
and l1
Assuming size of balloon negligible
Sid E.
How would I make a diagram of this question?
Report
11/01/20
Dr Gulshan S.
tutor
Draw a triangle with balloon at too point ( Vertex) Height y and base x. One angle theta1 for x1 and other theta 2 on x2 side
X1+x2 = 40 m =x
Assume balloon to be just a point ( as it’s very small as compared to sides of triangle
Report
11/01/20
Dr Gulshan S.
tutor
Opposite sides of triangle are l1 and l2
Report
11/01/20
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Sid E.
How would I make a diagram of this question?11/01/20