2 sin (x) - √3=0 . Find all the solutions in the interval of [0, 2pi)

Question

Can someone explain me the procedure of this type of question? Thank you

Answer 1

Just perform regular algebra to try to isolate "x". Then you will need to use the unit circle to find the exact answer.

2sin(x) - √3 = 0 [add √3 to both sides

2sin(x) = √3 [divide both sides by 2

sin(x) = √3/2

Now, look on the unit circle to find x = π/3 and 2π/3