What is the equation in slope-intercept form for the line parallel to y=-2x+10 that contains J(6,8)?

Answer 1

Hello, Breanna,

Parallel lines have the same slope. A line parallel to the one you reference would take the form y = -2x + b. We can calculate b by entering the point (6,8) and solving for b.

8 = -2*6 + b

b = 20

The line y = -2x + 20 is parallel and will intersect the point (6,8)

I hope this helps,

Bob

Answer 2

slope-intercept form is y=mx+b, where m = slope and b = y -intercept

to find equation of parallel line we need to find it's m and b.

line y=-2x + 10 has slope = -2, line parallel to it has m = slope = -2

so we have y = -2x + b. to find b we substitute point on line for x,y. that point is J(6,8)

8 = -2(6) + b

b = 20

so y = -2x + 20 is equation of parallel line.

Answer 3

Hello!

The line they give you is already in slope-intercept form (y=mx+b), which means that the number multiplied to the 'x' is the slope: -2

We want to use this slope for our line since parallel lines have the same slope and the question told us to make our new line equation parallel to their equation.

Now we can create a new line equation using this slope and the point they give you to use: (6,8)

This is the point-intercept form: y-y₁=m(x-x₁)

Leave the plain "y" and "x" alone as letters, replace the m with our slope number (-2), and replace y₁ and x₁ with the x & y from the point they give you:

y - 8 = -2 (x - 6) (distribute the -2)

y - 8 = -2x + 12 (neg times neg is pos) (then add 8 to both sides)

y = -2x + 20

(:

Answer 4

In order for lines to be parallel they must have the same slop

Therefore,

m = -2 for the parallel line

Now plug in (6,8) into the following slope intercept form equation

Y = mx + b

Y = -2x+b

8 = -2(6) + b

b = 8+12 = 20

b = 20

Y = -2x + 20