A 7.60 L container holds a mixture of two gases at 53 °C. The partial pressures of gas A and gas B, respectively, are 0.314 atm and 0.521 atm.

Question

If 0.150 mol of a third gas is added with no change in volume or temperature, what will the total pressure become?

Answer 1

Use the ideal gas law equation, PV = nRT to find the pressure P of the third gas using 0.150 moles (n).

Add that value to the sum of the pressures of the other 2 gases already present to get total pressure.

0.314 atm + 0.521 atm = 0.835 atm = pressure before adding the third gas.

0.835 atm + pressure of third gas = new total pressure