A mixture of He, Ne, and Ar has a pressure of 26.4 atm at 28.0 °C. If the partial pressure of He is 4.88 atm and the partial pressure of Ar is 1.35 atm, what is the partial pressure of Ne?

Answer 1

The sum of all partial pressures equals the total pressure

P_t = P_He + P_Ne + P_Ar

26.4 atm = 4.88 atm + 1.35 atm + P_Ne

P_Ne = 26.4 - 4.88 - 1.35

P_Ne = 20.2 atm