Patrick B. answered 11/01/20
Math and computer tutor/teacher
1) NULL HYpothesis is standard deviation = 0.3
2)
The test statistic formula is:
ChiSquareX_2 = (N-1)* (sample_standard_deviation)^2 / (hypothetical_standard_deviation)^2
The sample standard deviation is (10-1)*(0.309153126)^2 / (0.5)^2
= 3.440723591360587536
3)
With 29 df, Chi Square table via Excel says the p-value is
ChiSq.Dist(3.440723,29,true) = 0.055762895
4)
NULL Hypothesis ACCEPTED, as 0.05 < p-value
The statistical sample supports the hypothesis that
the standard deviation is 0.3