x is N(110.5,95.6).
Transform x to standard normal distribution (mean 0 SD 1) using z-score for single value:
z = (x - population mean) / SD = (x - 110.5)/95.6
P(x < 113.1) = P(z < (113.1-110.5)/95.6) = P(z < 0.03) = 0.5120 (from standard normal distribution table)
for sample mean, z-sore for mean:
z = (xbar - population mean) / SD/sqrt(sample size) = (xbar - 110.5)/95.6
P(xbar < 113.1) = P(z < (113.1 - 110.5)/(95.6/sqrt(221) = P(z < 0.4) = 0.6554.