chemistry class

Question

Combining 0.370 mol Fe2O3 with excess carbon produced 17.7 g Fe.

Fe2O3+3C⟶2Fe+3CO

What is the actual yield of iron in moles?

What is the theoretical yield of iron in moles?

What is the percent yield?

Answer 1

What is the actual yield of iron in moles?

*** 17.7 g Fe x 1 mol Fe/55.85 g = 0.317 moles

What is the theoretical yield of iron in moles?

*** 0.370 mol Fe2O3 x 2 mol Fe / mol Fe2O3 x 55.85 g Fe/mol = 41.33 g Fe

What is the percent yield?

*** 17.7 g / 41.33 g (x100) = 42.8% yield