J.R. S. answered 10/29/20
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0.0593 moles CaCl2 / x L = 0.810 moles CaCl2/1 L
x = 0.0593 / 0.810 = 0.0732 L = 73.2 mls
Ab B.
asked 10/29/20If 0.0593 mol CaCl2 is dissolved in water to make a 0.810 M solution, what is the volume of the solution?
J.R. S. answered 10/29/20
Ph.D. University Professor with 10+ years Tutoring Experience
0.0593 moles CaCl2 / x L = 0.810 moles CaCl2/1 L
x = 0.0593 / 0.810 = 0.0732 L = 73.2 mls
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