Jon S. answered 10/29/20
Patient and Knowledgeable Math and English Tutor
Ho: mu = 16.4
Ha: mu > 16.4
test statistic t = (sample mean - 16.4)/(standard deviation/square root(sample size)
= (16.6 - 16.4)/(0.4/sqrt(40)) = 3.16
degrees of freedom = 39
p-value = P(t > 3.16) with 39 DOF = 0.0015
critical value at alpha = 0.05, is t-score for 0.05 tail probability and 39 DOF ~ 1.684
reject Ho
G) There is enough evidence to support the claim that the mean of boxes is greater than 16.4 ounces.