Write the standard equation of a circle that passes through the point (2, 2) with its center at (1, -3).

Answer 1

Equation of circle = (x-h)^2 + (y-k)^2 = r^2, where (h,k) is center and r is radius.

center here (h,k) = (1,-3).

since circle passes through (2,2), radius is distance between (2,2) and (1,-3)

distance between two points (x1,y1) and (x2,y2) = sqrt((x2-x1)^2 + (y2-y1)^2)