A gas system has initial pressure and volume of 2790 torr and 14.32 L. If the volume changes to 16200 mL, what will the resultant pressure be in atm? (1 atm=760 torr)

Answer 1

Assuming the temperature is constant, we can use Boyle's Law:

P1V1 = P2V2

P1 = 2790 torr

V1 = 14.32 L

P2 = ?

V2 = 16,200 ml = 16. 2 L

Solving for P2 we have...

P2 = P1V1 / V2

P2 = (2790 torr)(14.32 L) / (16.2 L)

P2 = 2466 torr x 1 atm/760 torr = 3.245 atm