The 75th percentile corresponds to a z-score of of 0.67.
Since readings are N(0,1), the 75th percentile is 0.67 degrees C.
Melony M.
asked 10/29/20Assume that the readings at freezing on a batch of thermometers are Normally distributed with mean 0°C and standard deviation 1.00°C.
Find P75, the 75-percentile of the distribution of temperature readings. This is the temperature reading separating the bottom 75% from the top 25%.
The 75th percentile corresponds to a z-score of of 0.67.
Since readings are N(0,1), the 75th percentile is 0.67 degrees C.
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