B H.
asked • 10/28/20Angles in a Triangle
Given a triangle RST and point U on line RT, line segment RS is congruent to line segment ST. The measure of angle RST is 3x-48 and the measure of angle STU is 9x. Solve for x.
<a href="https://ibb.co/rHWJF4f"><img src="https://i.ibb.co/rHWJF4f/Impossible-Triangle-Question2.png" alt="Impossible-Triangle-Question2" border="0"></a>
This was an actual question on my son's 9th grade Geometry test. It looks like there is a typo somewhere because I'm 95% sure there is no solution.
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1 Expert Answer
Hi,
the third angle in the triangle angle SRT would also be 9x because those two sides were congruent.- it is an isosceles triangle
use sum of 3 interior angles = 180 and solve for x
hope this helps
B H.
I guess my diagram didn't post on there. None of the angles in the triangle can have a measure of 9x. STU is 'outside' of the triangle. So angles SRT and STR are congruent and have a measure of 180 - 9x. I can solve for x (180 - 9x + 180 - 9x + 3x - 48 = 180) and get x = 8.8. But that would mean the measure of angle RST is negative, since RST = 3x - 48.
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10/29/20
Vidya V.
tutor
Ok. Yes I didn’t see the diagram and thought U was a point on the segment RT. Now I see your point. I am also confused? Please post the answer if there is one! Thank you.
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10/29/20
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10/28/20