Phase Change Energetics

Question

The following information is given for iron at 1 atm:

boiling point = 2750 °C	Hvap(2750 °C) = 354 kJ/mol
melting point = 1535 °C	Hfus(1535 °C) = 16.2 kJ/mol
specific heat solid = 0.452 J/g°C
specific heat liquid = 0.824 J/g°C

BLANK  kJ are required to melt a 34.4 g sample of solid iron, Fe, at its normal melting point

Answer 1

C'mon, look at the table and see that it takes 16.2 kJ/mol to melt iron at its melting point. That's what ∆Hfus tells you. So convert 34.4 g of iron to moles and iron and multiply that by kJ/mol to get kJ