how do i write an equation parallel to y=-2x+3 through the point (-1,4)

Answer 1

Given:

Y = -2x+3

Find:

Equation parallel to Y = -2x +3 at point (-1,4)

Solution:

In order for the equation to be parallel the slope has to match in magnitude and sign.

Equation given already in slope intercept form Y = mx + b

Because of this m = -2

Parallel equation must follow this format

Y = -2x + b

Now apply desired points

4 = -2 (-1) + b

4 - 2 = b

b =2

Therefore,

Parallel equation must be:

Y = -2x + 2

Plot both equations to prove out this solution :)

Answer 2

Y = M(X) + B M is the slope, B is the Y intercept

To write an equation of a line that has a parallel slope, that means the slopes are the same, so, the slope of the first and second equation will be (M) = -2

1. Second equation will be: Y = -2(X) + B
2. Now use the point given (-1,4) for the X and Y in the above equation and solve for B
3. 4 = -2(-1) + B
4. 4 = 2 + B
5. B = 2
6. Put the B and M together and there's your equation: Y = -2(X) + 2

I hope this helps you understand the process!!! Let me know if you still have questions!